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Report: Shortstop Stephen Drew, Red Sox agree to one-year deal

Stephen Drew hasn't played since celebrating Boston's World Series victory last season. (Elsa/Getty Images) Stephen Drew hasn't played since celebrating Boston's World Series victory last season. (Elsa/Getty Images)

Stephen Drew is back with the Red Sox.

After an offseason spent wondering where the free agent 31-year-old shortstop would wind up, Drew agreed to return to the team he helped win the 2013 World Series, according to Fox Sports' Ken Rosenthal on Tuesday. The deal is reportedly for the rest of the season and is worth $14 million ($10 million prorated for the time he missed), which is what he would have received had he accepted Boston's qualifying offer this offseason, according to Gordon Edes of ESPNBoston.com.

The Red Sox will also not be compensated with a draft pick since Drew resigned with them.

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Drew will not be in uniform for Boston's game Tuesday night against the Blue Jays at Fenway Park.

He hit .253 with 13 homers and 67 RBIs in 124 games for the Red Sox last season, his first in Boston. He hit only .111 in the playoffs but had a big home run in Game 6 of the World Series.

Drew is a career .264 hitter with a .764 OPS in eight big league seasons with the Diamondbacks (2006-12), A's (2012) and Red Sox (2013).

Boston (20-23) has lost four in a row and is in fourth place in the AL East, three games behind the Yankees. Xander Bogaerts, Drew's replacement at shortstop, is hitting .269 with two homers and seven RBIs in 41 games. The 21-year-old has 38 strikeouts in 145 at-bats.

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