Seahawks DE Jadeveon Clowney Named NFC Defensive Player of the Week
On the heels of arguably the most dominant outing of his six-year NFL career, Seahawks defensive end Jadeveon Clowney has been named the Week 10 NFC Defensive Player of the Week.
Starring in a 27-24 overtime win over the 49ers, Clowney tormented San Francisco’s offensive line all night long from multiple alignments, finishing with five tackles, five quarterback hits, one sack, and a game-changing fumble recovery.
“I thought Jadeveon Clowney was fantastic tonight,” coach Pete Carroll said after the game. “Just when he was close, he was causing problems and scored again.”
With Seattle trailing 10-0 late in the first half, defensive tackle Jarran Reed powered into the backfield and stripped the football out of quarterback Jimmy Garoppolo’s hands. Flying off the right side, Clowney scooped up the fumble and returned it 10 yards for a touchdown, cutting the deficit to three points.
Later in the third quarter, Clowney got under the pads of tackle Mike McGlinchey and drove him directly into Garoppolo’s lap, sacking him and forcing a fumble. Teammate Poona Ford recovered and just three plays later, Russell Wilson hit Jacob Hollister for a three-yard touchdown to give the Seahawks their first lead.
During overtime, Clowney came up in the clutch again with a key run stuff to thwart a 49ers drive and force them to kick a 47-yard field goal. Kicker Chase McLaughlin wound up hooking the kick wide left, giving the Seahawks another opportunity to win the game.
“Clowney was playing lights out today,” Wilson said after the game. “That’s why we got him. He’s been a force throughout his whole career… It’s great to have him. The plays he was making were incredible.”
Clowney had previously been named AFC Defensive Player of the Week once with the Texans, garnering the honors in Week 4 of the 2018 season.