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BREAKING: Chicago Bulls Reportedly Signing Recent Milwaukee Bucks Player

According to ESPN's Adrian Wojnarowski, the Chicago Bulls will sign Jevon Carter.

Many moves around the NBA are being reported on Friday evening, as June 30 marks the first day of free agency. 

According to ESPN's Adrian Wojnarowski, the Chicago Bulls will sign Jevon Carter. 

Via Wojnarowski: "Free agent guard Jevon Carter has agreed on a three-year, $20 million deal with the Chicago Bulls, his agents Mark Bartelstein and Reggie Brown of @PrioritySports tell ESPN. Carter leaves the Bucks to bring Bulls his perimeter toughness."

Carter spent this past year playing for the Milwaukee Bucks and averaged 8.0 points, 2.5 rebounds and 2.4 assists per contest while shooting 42.3% from the field and 42.1% from the three-point range in 81 games. 

He played a crucial role in the Bucks finishing as the first seed in the Eastern Conference and having the best record in the NBA (58-24). 

In addition to the Bucks, the former West Virginia star has also spent time with the Brooklyn Nets, Phoenix Suns and Memphis Grizzlies (he was the 32nd pick in the 2018 NBA Draft). 

His career averages are 5.4 points, 1.9 rebounds and 1.7 assists per contest while shooting 40.0% from the field and 39.7% from the three-point range. 

There is no question this will be a significant pick-up for the Bulls, who were in need of guard depth and three-point shooting. 

Last year, they finished as the tenth seed in the Eastern Conference with a 40-42 record. 

The Bulls beat the Toronto Raptors in their first play-in tournament game but were eliminated by Jimmy Butler and the Miami Heat in the second.