Giants Agree to Terms with IDL A'Shawn Robinson

New York adds more depth to the defensive front with a big run-stuffer.

The New York Giants have agreed to terms with defensive lineman A'Shawn Robinson, most recently with the Rams, on a one-year deal worth up to $8 million, per the NFL Network, and as confirmed by the Giants.

The #Giants have agreed to terms with #Rams FA DT A’Shawn Robinson, continuing to beef up their defensive front right before the Draft, sources tell me and @MikeGarafolo. He gets a 1-year deal worth up to $8M max value with the opportunity to find a home with NYG. pic.twitter.com/K53jVNi77Y

— Ian Rapoport (@RapSheet) April 24, 2023

Robinson, 6-foot-4 and 330 pounds, was drafted by the Lions in the second round of the 2016 draft. He spent the first four years of his career with the Lions before moving on to the Rams in 2020 as an undrafted free agent. 

While in Los Angeles, he appeared in 35 games, starting 24 over his final two years with the Rams and winning a Super Bowl championship with the organization during the 2021 season.

Robinson has appeared in 93 career games with 61 starts. He has 293 total tackles, 20 tackles for a loss, 20 quarterback hits, and seven sacks over his career. 

Primarily a B-gapper, Robinson, who played his college ball at Alabama, has only played one full season's worth of games, that in 2017.

A sure tackler--last season, in 10 games, he only logged a 4.5 percent missed tackle rate--Robinson has finished with a PFF run-defense grade of above 68.7 in his last two seasons.

Robinson is coming off a torn meniscus in his knee that prematurely ended his 2022 season. 

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