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Seymour took home $59,295 after being eliminated in the fifth day of competition.

By Michael Shapiro
July 10, 2019

Former Patriots defensive end Richard Seymour was eliminated from the World Series of Poker on Wednesday night after an impressive five-day run. 

Seymour finished in 131st place out of 8,569 entrants. He won $59,295 for his performance, a nice payday considering the $10,000 entry. The World Series of Poker winner will receive $10 million. 

Seymour is no poker novice, previously winning nearly $500,000 in his poker career, per ESPN's Tim Fiorvanti. He has a long way to go to match his NFL earnings, though, which total $89.5 million over 12 seasons.

The Georgia product retired from the NFL in 2012 after 12 seasons. He played for the Patriots from 2001-08 before finishing his career with the Raiders. Seymour earned three All-Pro honors and won three Super Bowls in New England. 

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HOLE YARDS PAR R1 R2 R3 R4
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HOLE YARDS PAR R1 R2 R3 R4
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Eagle (-2)
Birdie (-1)
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