LEADING OFF: Quintana debuts for Cubs, Yanks-Bosox twinbill
A look at what's happening all around the majors today:
RIGHT ON Q
Jose Quintana makes his debut for the Chicago Cubs when he starts at Baltimore. Trying to make a playoff push, the World Series champions acquired the All-Star lefty from the crosstown White Sox on Thursday for four minor leaguers, including two top prospects. Quintana is 4-8 with a 4.49 ERA this year, including a loss at Camden Yards on May 7.
The Yankees and Red Sox are set for a day-night doubleheader at Fenway Park, a day after they played nearly six hours and 16 innings before New York won 4-1. With the way these AL East rivals drag through games, no telling what time in the wee hours they might eventually end. David Price, with a career 14-11 record in 37 games against the Yankees, starts the nightcap for first-place Boston against Masahiro Tanaka.
The NL Central-leading Brewers will see how star slugger Ryan Braun is feeling going into the series finale vs. Philadelphia at Miller Park. The former NL MVP has struggled with a strain in his left calf for several weeks, and manager Craig Counsell says the outfielder will be evaluated daily for the rest of the season. Braun has been on the disabled list twice this season with calf trouble.
Homer Bailey faces Washington less than a month after the NL East leaders ruined his season debut. The 31-year-old Bailey, who has thrown two no-hitters for the Reds, was tagged for eight runs on six hits and three walks in just 1 2/3 innings June 24 at Nationals Park. Often injured, that was his first game in the majors since last August. He's 2-2 going into this start at Cincinnati.
BACK ON THE HILL
Dodgers lefty Rich Hill is scheduled to start the series finale in Miami for the NL West leaders. Hill made his most recent appearance at Marlins Park last September, when he threw seven perfect innings before manager Dave Roberts pulled him, mindful the veteran had been sidelined by a blister earlier in the season. Three relievers completed a two-hit shutout.